Question

4 years ago, father’s age was 6 times of his son. 12 years from now, father’s age will be twice of his son, what is the present age ratio of father and son?

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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• At present,

Let the son's age be 'x'.


• 4 years ago ,

Son's age = x - 4

Father's age = 6 (x - 4) = 6x - 24


• So, Father's present age = 6x - 24 + 4
= 6x - 20


• 12 years after,

Son's age = x + 12

Father's age = 6x - 20 + 12 = 6x - 8


• But, according to the question, after 12 years, father's age = 2 × son's age.

=> 6x - 8 = 2(x + 12)

=> 6x - 8 = 2x + 24

=> 6x - 2x = 24 + 8.

=> 4x = 32

=> x = 32/4

=> x = 8


• Hence, son's present age = x = 8 years.

• And, father's present age = 6x - 20
= 6 × 8 - 20
= 48 - 20
= 28 years.


• Now, the ratio of the present ages of the father and his son

= Father's age : Son's age

= 28 : 8

= 7 : 2

$<marquee>Hence, your answer is 7 : 2.</marquee>$
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Thank you.. ;-)