Question

4 years ago george was 4 times older than his daughter. after four years george will be 2 years more than two times the age of his daughter. find the present age of george and his daughter

Answer 1

let the present age of George be xyears .
"the present age of his daughter be y years .
4years ago :age of George=x-4years
age of daughter =y-4years .
ATP:
x-4=4(y+4 )
x-4=4y+12
x=4y+12-----------(1)
After 4years :
George age =x+4
daughter age =y+4
ATP:
x+4=2(y+4+2)
x+4=2y+8+4
x+4=2y+12 ---------(2)
putting the value of xfrom equation 1in2
x+4 =2y+12
4y+4 =2y+12
4y-2y=12-4
2y=8
y=4years
putting the value of y in eq. 1
x=16+12
x=28 years
Hope it helped .

Answer 2

Let the present age of George be xyears .

"the present age of his daughter be y years .

4years ago :age of George=x-4years

age of daughter =y-4years .

ATP:

x-4=4(y+4 )

x-4=4y+12

x=4y+12-----------(1)

After 4years :

George age =x+4

daughter age =y+4

ATP:

x+4=2(y+4+2)

x+4=2y+8+4

x+4=2y+12 ---------(2)

putting the value of xfrom equation 1in2

x+4 =2y+12

4y+4 =2y+12

4y-2y=12-4

2y=8

y=4years

putting the value of y in eq. 1

x=16+12

x=28 years