4 years ago Meera's age is 3 times of manu's age. After 8 years Meera's age is twice of the manu's age. Find the present age of both.
Answers
Answered by
129
Answer :
Let the present age of Meera be x years and Manu's age be y years respectively.
Their ages four years ago,
- Meera's age = (x – 4) years
- Manu's age = (y – 4) years
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- Four years ago, Meera's age was three times the age of Manu.
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Also,
- After eight years Meera's age is twice the age of Manu.
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Their ages after eight years,
- Meera's age = (x + 8) years
- Manu's age = (y + 8) years
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Answered by
86
Answer:
Given :-
- 4 years ago Meera's age is 3 times of Manu's age.
- After 8 years Meera's age is twice of the Manu's age.
To Find :-
- What is their present ages.
Solution :-
Let,
❒ 4 years ago their ages will be :
According to the question,
4 years ago, Meera's age is 3 times of Manu's age.
❒ After 8 years their ages will be :
According to the question,
After 8 years Meera's age is twice of the Manu's age.
By subtracting the equation no 1 from the equation no 2 we get,
Again, by putting the value of b in the equation no 1 we get,
Hence, their required present ages are :
➲ Present Age Of Meera :
➲ Present Age Of Manu :
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