Question

4 years ago meera was 3 times as old as manu.8years later Meera would be twice as old as Manu. How old are they now?​

Answer 1

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Present age of a = 50 years and of b = 20 years

To find:

Present ages of a and b = ?

Solution:

Given :

1. Five years ago a was three times as old as b

2. Ten years later a shall be twice older than b.

Assume that present age of a as x and that of b as y.

Five years ago, a was thrice as old as b

i.e. age of a was x - 5 and age of b was 3(y-5)

x - 5 = 3 (y - 5)

x - 5 = 3y - 15

x - 3y = -15+5

x - 3y = -10 ---------(1)

Ten years later, a shall be twice as old as b

i.e. age of a will be x + 10 and age of b will be 2(y+10)

x + 10 = 2 (y + 10)

x + 10 = 2y + 20

x - 2y = 20-10

x - 2y = 10 ---------(2)

By elimination method, we get

x - 3y = -10

x - 2y = 10

- y = -20

y = 20 i.e. present age of b

Substituting y = 20 in equation 1, we get

x - 3y = -10

x - 3(20) = -10

x - 60 = -10

x = -10 + 60

x = 50 i.e. present age of a.

Answer 2

4 years ago

Manu's age=x

Meera's age=3x

Present age,

Manu's age =x+4

Meera's age=3x+4

After 8 years,

4 years ago,

Manu's age=x+4+8

=x+12

Meera's age=3x+4+8

=3x+12

Meera would be twice as old as Manu means

2(x+12)=3x+12

2x+24=3x+12

3x-2x=24-12

x=12

so present age, of Manu=x+4

12+4=16

present age of Meera=3x+4

=3×12+4

=36+4=40

hopes you it will helps you