4 years ago, Swapana mother was 3 times as old as swapana.After 6 years she will be twice as old as swapana.present age of Swapana mother is
Answers
Step-by-step explanation:
4 years ago,
Let,
- The age of Swapana = x
- The age of Swapana's mother = 3x
★ Present age,
- Present age of Swapana = x + 4
- Present age of Swapana's mother = 3x + 4
After 6 years,
- Age of Swapana = x + 4 + 6 = x + 10
- Age of Swapana's mother = 3x + 4 + 6 = 3x + 10
Also,
Swapana's mother will be twice as old as Swapana
★ According to the Question :
⇒ 2 (x + 10) = 3x + 10
⇒ 2x + 20 = 3x + 10
⇒ 20 - 10 = 3x - 2x
⇒ 10 = x
___________________________
• Present age of Swapana = x + 4
⇒ x + 4
⇒ 10 + 4
⇒ 14
Present age of Swapana = 14 years
___________________________
• Present age of Swapana's mother = 3x + 4
⇒ 3x + 4
⇒ 3 (10) + 4
⇒ 30 + 4
⇒ 34
Present age of Swapana's mother = 34 years
Therefore, present age of Swapana's mother is 34 years.
Given :-
4 years ago, Swapana's mother was 3 times as old as Swapana. After 6 years she will be twice as old as Swapna.
To Find :-
The Present age of Swapana's mother
Solution :-
Let the age of Swapana be x and her mother age be y
Four years ago
Age of Swapana = x - 4
Age of mother = y - 4
According to the question
Mother's age = 3(Swapana Age)
y - 4 = 3(x - 4)
y - 4 = 3x - 12
y - 3x = 4 + (-12)
y - 3x = 4 - 12
y - 3x = -8 (..i)
After 6 years
Age of Swapana = x + 6
Age of mother = y + 6
Mother's age = 2(Swapana Age)
y + 6 = 2(x + 6)
y + 6 = 2x + 12
y - 2x = 12 - 6
y - 2x = 6 (..ii)
On subtracting
y - 3x - (y - 2x) = -8 - 6
y - 3x - y + 2x = -14
-3x + 2x = -14
-x = -14
x = 14
Using Eq 2
y - 2(14) = 6
y - 28 = 6
y = 28 + 6
y = 34
Hence
Age of her mother is 34 years.