Question

4 years back, A's age was 4 times that B's age . what is A's present age, if after 3 years , B's age will be 1/3rd of A's age
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Answer 1

Answer:

The present age of A = 60

and of B = 18

I hope this will help you .

Thank you.

Answer 2

Given:

4 years back, A's age was 4 times that of B's age. After 3 years, B's age will be 1/3rd of A's age.

To find:

The A's present age.

Solution:

The present age of A is 60 years.

To answer this question, we will follow the following steps:

Let the present age of A and B be x and y years respectively.

4 years ago,

A's present age = (x - 4) years

B's present age = (y - 4) years

Now,

According to the question, we have,

$x - 4 = 4(y - 4)$

$x - 4y + 12 = 0 \: (i)$

After 3 years,

A's present age = (x + 3) years

B's present age = (y + 3) years

So,

$\frac{1}{3} (x + 3) = y + 3$

$x + 3 = 3y + 9$

$x - 3y - 6 = 0 \: (ii)$

Now,

After subtracting (i) from (ii), we get

$y = 18 \: years$

On putting the value of y in (ii), we get

$x - 3(18) - 6 = 0$

$x = 60 \: years$

Hence, A's present age is 60 years.