4(z -5)+ 2 = 4z- 18 How many solutions does this equation have? I will give brainliest
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Answer: There are infinitely many solutions to the equation.
Solution: Let's simplify the left hand side of the equation, we get 4(z-5)+2=4z-20+2=4z-18. So, because the left hand side and the right hand side are both equal to 4z-18, we get the equation 4z-18=4z-18, which will be true for any z value(you can get all values with z in it to the left side and all numbers to the right side to get 0=0, which will be true for any z value, thus the original equation also is true for any z value).
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