(40×11/5)÷(3/7×x)=4/3 isme x ka Kya man hoga
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{40 × (11/5) } ÷ { (3/7) × x } = 4/3, दिए गए समीकरण में 'x' का मान है 154 ।
• BODMAS के नियम का पालन करते हुए, सर्वप्रथम ब्रैकेट में संलग्न व्यंजकों को सुलझाना होगा।
• अतएव,
{40 × (11/5) } ÷ { (3/7) × x } = 4/3
=> (8 × 11) ÷ (3x / 7) = 4/3
=> 88 × (7 / 3x) = 4/3
=> (88 × 7 × 3) / (3 × 4) = x
=> 22 × 7 = x
=> x = 154
x का मान 154 है।
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