Question

40 3.2 kg of ice at -100
of ice at -10°C just melts with m mass of
at 100°C, then m is equal to
(1) 800g
(2) 625 g
(4) 325 g
(3) 425g​

Answer 1

mass of steam should be 425 g .

3.2 kg of ice at -10°C just melts with m mass of steam at 100°C, then m is equal to...

mass of ice , m = 3.2kg = 3200g

initial temperature, Ti = -10°C

final temperature , Tf = 0°C

heat required to increase the temperature of ice, H1= ms∆T

= 3200g × 0.5 cal/g.°C × (0° -(-10°c))

= 3200 × 0.5 × 10

= 16000 cal = 16Kcal

and heat required to melt the ice, H2 = mLf

= 3200g × 80 cal/g

= 3200 × 80 cal

= 256000 cal = 256 Kcal

now, total hear required = 256 + 16 = 272Kcal

from calorimetry ,

heat gained by ice = heat lost by steam

or, 272Kcal = m Lv + ms∆T

or, 272Kcal = m(540 + 1 × 100) cal

or, 272000 cal = m × 640

or, m = 425g

hence, mass of steam should be 425 g

also read similar questions :

Define Latent heat of vaporization and Latent heat of fusion

https://brainly.in/question/410573

A block of 100g of ice at 0˚C is added to some water at 40˚C contained in a vessel of negligible water equivalent. What ...

https://brainly.in/question/3551015