40+3a-a² how to factorise
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-a^2+3a+40
=-a^2+3a+40
=-a^2+8a-5a+40
=a(-a+8)+5(-a+8)
=(a+5)(-a+8)
=(a+5)(a-8){transposing 8 and a}
=-a^2+3a+40
=-a^2+8a-5a+40
=a(-a+8)+5(-a+8)
=(a+5)(-a+8)
=(a+5)(a-8){transposing 8 and a}
u wanted it again right ?
yes
is it enough?
yes
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=-a^2+3a+40
=-a^2+8a-5a+40
=a(-a+8)+5(-a+8)
=(a+5)(-a+8)
=(a+5)(a-8){transposing 8 and a}