Question

40 + 3x minus x^2=0 solve quadratic equation ​

Answer 1

Answer:

8 , 5

Step-by-step explanation:

40 + 3x - x² = 0

x² - 3x - 40 = 0

x² - 8x + 5x - 40 = 0

x(x - 8) + 5(x - 8) = 0

(x - 8) (x - 5) = 0

thus we have

x - 8 = 0 or x - 5 = 0

x = 8 or x = 5 ans

Answer 2

Answer:

$- {x}^{2} + 3x + 40 = 0$

${x}^{2} - 3x - 40 = 0 \\ {x}^{2} - 8x + 5x - 40 = 0 \\ x(x - 8) + 5(x - 8) = 0 \\ (x - 8)(x + 5) = 0 \\ x = 8 \: or \: x = - 5$

Hope this is helpful......