Question

40+{[42+f]-8/f}*10 pls ans this

Answer 1

$40 + [(42 + f) - \frac{8}{f} ] \times 10 \\ \\ \\ \\ 40 + ( \frac{42f + {f}^{2} - 8}{f} ) \times 10 \\ \\ 40 + \frac{420f + {10f}^{2} - 80 }{f} \\ \\ \frac{40f + 420f + {400f}^{2} - 3200 }{f} \\ 440f + {400f}^{2} - 3200 = f$