Math, asked by cmallikarjuna2200, 11 months ago

ఒక పాఠశాలలో 40% మంది పుట్ బాల్, 50% మంది క్రికెట్ ఆడుతారు. 18% మంది రెండూ ఆడరు. అయిన రెండు
ఆటలు ఆడువారు ఎంత శాతము?
1) 10%
2) 32%
3) 22%
4)8%​

Answers

Answered by mysticd
2

Answer:

Option (4) is correct

Step-by-step explanation:

Total students = 100

Number of players who play football =n(F) = 40

Number of players who play Cricket=n(C) = 50

Number of students who play nothing =n(FUC)' = 18

Number of players =n(FUC) = 100 - n(FUC)'

= 100- 18

= 82

Number students who play both = n(FnC)

Now,

n(FnC) = n(F)+n(C)-n(FUC)

= 40+50-82

= 90 - 82

= 8

Therefore,

Option (4) is correct

•••♪

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