ఒక పాఠశాలలో 40% మంది పుట్ బాల్, 50% మంది క్రికెట్ ఆడుతారు. 18% మంది రెండూ ఆడరు. అయిన రెండు
ఆటలు ఆడువారు ఎంత శాతము?
1) 10%
2) 32%
3) 22%
4)8%
Answers
Answered by
2
Answer:
Option (4) is correct
Step-by-step explanation:
Total students = 100
Number of players who play football =n(F) = 40
Number of players who play Cricket=n(C) = 50
Number of students who play nothing =n(FUC)' = 18
Number of players =n(FUC) = 100 - n(FUC)'
= 100- 18
= 82
Number students who play both = n(FnC)
Now,
n(FnC) = n(F)+n(C)-n(FUC)
= 40+50-82
= 90 - 82
= 8
Therefore,
Option (4) is correct
•••♪
Similar questions
English,
6 months ago
Environmental Sciences,
11 months ago
Science,
11 months ago
Biology,
1 year ago