Question

40
62
. What is the sum of the first 10 terms of an A.P. 41, 36, 31, 26, ..
(Dcon
non
TI 105​

Answer 1

Answer:

here, 1st term = 41

common difference = 5

then, sum of first 10 terms = (10/2)(41 + 41 + 9(5))

= 5 (82 + 45)

= 5 (127) = 635. ans