Math, asked by pushpahbn, 12 hours ago

40. A capsule is in the shape of a cylinder with hemisphere attached to both the base.The total surface area of the capsule is
A) 20r²+2nrh
B) 41r?+or?h
C) 40r +2nrh
D) nr+2nrh 2

answer please​

Answers

Answered by sprasoon484
0

220

Given:

Length of Capsule (l) = 14 mm

Diameter of Capsule = Diameter of Cylinder =5 mm

Radius =

2

Diameter

Therefore, Radius of each Hemisphere = Radius of Cylinder = r =

2

5

= 2.5 mm

Length of Cylinder = AB = Total length of Capsule - Radius of left Hemisphere - Radius of Right Hemisphere

=14−2.5−2.5=9 mm

Surface Area of Capsule = Curved Surface Area of Cylinder + Surface Area of Left Hemisphere + Surface Area of Right Hemisphere

=2πrl+2πr

2

+2πr

2

=2πrl+4πr

2

=2×

7

22

×2.5×9+4×

7

22

×2.5

2

=

7

22

[45+25]=

7

22

×70=220 mm

2

Mark me as barilinest....

Answered by AngeIianDevil
29

\Large\mathtt\green{ }\huge\underline\mathtt\red{Answer : }

Given,

Length of Capsule (l) = 14 mm

Diameter of Capsule = Diameter of Cylinder =5 mm

Radius = 2Diameter

Therefore, Radius of each Hemisphere = Radius of Cylinder = r = 25 = 2.5 mm

Length of Cylinder = AB = Total length of Capsule - Radius of left Hemisphere - Radius of Right Hemisphere 

 =14−2.5−2.5=9 mm

Surface Area of Capsule = Curved Surface Area of Cylinder + Surface Area of Left Hemisphere + Surface Area of Right Hemisphere

    =2πrl+2πr2+2πr2

    =2πrl+4πr2

     =2×722×2.5×9+4×722×2.52

   =722[45+25]=722×70=220 mm2

_______________________________

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