Question

40. A rocket of initial mass 6000kg ejects mass at
constant rate of 200 kg/sec. with constant
relative speed of 800 m/sec. The acceleration
of the rocket after 5 sec is (neglect gravity)​

Answer 1

Answer:

Therefore the acceleration of the rocket is 32 m/s^2

Explanation:

According to the problem the rocket is ejected at a specific rate and speed

Let the acceleration is a

Therefore a= vr/m dm/dt  

μ= 200kg/s

As the mass,m is varying                    

m=m0−μt [ μ= the ejection rate, t= the time]

  =6000−200×5  

  =  5000kg

Now as the relative velocity is given vr= 800 m/s

Therefore the acceleration will be:

a= 800/5000 x 200

 = 32 m/s^2

Answer 2

Answer:

Explanation:the answer is attached in the attached photo