Question

40. A tree is broken at a height of óm from the ground and its top touches 3
the ground at a distance of 8m from the base of the tree. Find the original
height of the tree.​

Answer 1

Answer:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)

2

+(AB)

2

+(BC)

2

⇒(AC)

2

=(12)

2

+(5)

2

⇒(AC)

2

=144+25

⇒(AC)

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.