Question

40% An iron sphere of mass 100 Kg is suspended freely from a rigid support by means of a rope of length 2m. The horizontal force required to displace it through an angle 60° from the mean position is dd nt of 1) 490/3N 2) 980/3N 3) 490 N 13 4) 980 N V3​

Answer 1

Answer: 2. 980√3N

Step-by-step explanation: mass of sphere (m) =100 Kg

Balancing vertical forces, we get  T cos 60^o  = mg

∴  T × 0.5 = 100 × 9.8

T = 1960 N    

Force required to displace the sphere   F=T sin(60^o )

F = 1960 ×√3/2= 980√3N