40 चे असे दोन भाग करा की त्याच्या गुणाकार व्यस्तांकांची बेरीज .8/75
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Answer:
Let the numbers be a and b
a+b=40
∴a=40−b
Sum of their reciprocals is
75
8
a
1
+
b
1
=
75
8
ab
a+b
=
75
8
ab=
8
75×40
=375
b(40−b)=375
b
2
−40b+375=0
b
2
−25b−15b+375=0
b(b−25)−15(b−25)=0
(b−15)(b−25)=0
b=15,25
Hence, the two numbers are 15 and 25.
Step-by-step explanation:
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