Question

40 caloties of heat is given to 1 gm of ice at -10 degree celcius what is final temperature

Answer 1

Let the final temperature of mixture be t.

Heat lost by water in calories,

  H  

1

​  

=19×1×(30−t)

       =570−19t

Heat taken by ice, H  

2

​  

=ms  

i

​  

Δt+mL+ms  

w

​  

t

                                   =5×(0.5)20+5×80+5×1×t

According to principle of calorimetry,

   H  

1

​  

=H  

2

​  

 

   5×(0.5)×20+5×80+5t=570−19t

⇒24t=570−450=120

⇒t=5

December 27