40 dozen oranges were purchased at rupees 18 per dozen.half pf them were sold at rupees 2 per orange. by that time, 20 oranges were rot .the remaining oranges were sold at rupees 1.25 each.calculate the profit or loss percent .
Answers
Answer:
Total cost of oranges
CP = 18*40 = 720
Selling price of 20 dozen oranges
SP1 = 2*12*20 = 480
Selling of remaining oranges
SP2 = (20*12 - 20)*1.25 = 220*1.25 = 275
Profit % ={ [(SP1 + SP2) - CP] /CP}*100
= [(755 - 720)/720]*100
= 350/72
= 4.86%
Answer:
total cost of oranges = 18×40
C.P. = 720 rupees
S.P. of 20 dozen oranges = 2×20×12 ( 1 dozen=12)
S.P.1 = 480 rupees.....(i)
S.P. of remain oranges = (12×20-20)×1.25 (we subtract 20 because 20 orange were rotten)
S.P.2 = 275 rupees......(ii)
sum of S.P. = S.P.1 + S.P.2
= 480 + 275
= 755 rupees
it is a profit because S.P. > C.P.
therefore
Profit% = sum of S.P. - C.P./C.P. ×100
Profit% = 755 - 720/720×100
Profit% = 35/720×100
Profit% = 4.861%