Question

40. Find the least number which when divided by 12, 16, 24 and 36 leaves a remainder 7 in each case.​

Answer 1

Answer:

Step-by-step explanation:

Least number when divided by 12,16,24,36 and leaves remainder 0

=LCM of 12,16,24,36

So,LCM leaves remainder 0

So, Required number will be 7 more than LCM

∴ Required number=LCM+7

Factors of 12=2×3×2

Factors of 16=2×2×2×2

Factors of 24=2×2×2×3

Factors of 36=2×2×3×3

∴ LCM=2×2×2×2×3×3=16×9=144

So, Required number=LCM+7=144+7=151

Answer 2

Answer:

79

Step-by-step explanation:

Least no. = 7 + LCM of 12,16,24,36

= 7 + 72

= 79

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