Math, asked by arun55551, 6 months ago

40. Find the smallest number of five digits which when
divided by 52, 56, 78 and 91 leaves remainders 28, 32,
54 and 67 respectively.
a) 10896 b) 10196 c) 10496 d) 10696​

Answers

Answered by arif1234538
0

thanks thanks thanks

B should be the answer

Answered by mauryasp191
0

Answer:

b is your correct answer

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