Math, asked by Anonymous, 5 months ago


40. Five years hence, the age of Jacob will be three times that of his son. Five years ago. Jacob's
age was seven times that of his son. What are their present ages?​

Answers

Answered by MissLaiba
7

Step-by-step explanation:

Let 'x' be the present age of jacob and 'y' be the age of his son

As per question

x+5=3(y+5).....(1)

x−5=7(y−5).......(2)

Adding (1) and (2)

2x=3y+15+7y−35

2x=10y−20

x=5y−10...(3)

Putting (3) in (1)

5y−5=3y+15

2y=20

y=10

Putting in (3)

x=5×10−10

x=40

Therefore Present age of Jacob is 40 years and his son is 10 years.

Answered by Smrutipratikshya
0

Answer:

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