Physics, asked by qamar24567890, 7 months ago

40 g of oil at 20C is mixed with 60g oil at 80C .What will be the final temperature of mixture

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Answers

Answered by seemachavi
1

Explanation:

Generally, specific heat is a function of temperature itself. But, in current problem variation of 20 degree C will not change the value of specific heat significantly. A simple energy balance is used for the system(assuming there is no transfer of heat to the surrounding):

50*4.2*(40-T)= 75*4.2*(T-20)

T= 28 C

(Strictly speaking, in real scenario temperature of water will be less than 28 degree C, because some part of heat will be transferred to the surrounding. This the maximum limit of the temperature which can be attained at thermal equilibrium.)

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Answered by CunningKing
27

Let the final temperature be T.

60 × 4.2 × (80 - T) = 40 × 4.2 × (T - 20)

⇒252 × (80 - T) = 168 × (T - 20)

⇒20160 - 252T = 168T - 3360

⇒20160 + 3360 = 168T + 252T

⇒23520 = 420T

⇒T = 23520/420

⇒T = 56

So, the final temperature will be 56°C.

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