Question

40 gf and 60 gf two weight are suspended at 0 mark and 100 cm mark of a meter scale. The point of equilibrium will be: *​

Answer 1

Let the meter graph be balanced at x centimeter mark on the scale.

At the balancing condition, Anticlock wise moment must be equal to clock wise moment.

Clockwise moment, about the balancing point is

= moment by 80 pq

=80pq×(80−x)centimeter

=6400pqcentimete−80xpqcentimeter..(1)

Anticlock wise moment about the balancing point is

= moment by 10 pq+ moment by 50 pq

=10pq×(x−10)+50pq×(x−50)

=10xpqc,−100pqcm+50xpqcm−2500pqcentimeter .(2)

At the balancing condition, Clock wise = Anti clock wise moments.

6400−80x=100x−100+50x−2500

6400+2600=140x⇒140x=8000

x=

140

8000

=64.28

It is balanced at 64.28 centimeter from the beginning.

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