40 gram of metal oxide contains 4 gram of oxygen the equivalent weight of metal is
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Answered by
4
Answer:
Equivalent mass of a metal is defined as the mass which combines with 8 gram of oxygen or 35.5 grams of chlorine or 1 gram of hydrogen.
Given: Mass of metal oxide = 40 g
mass of oxygen = 4 g
Thus mass of metal = Mass of metal Oxide - mass of oxygen = ( 40-4) g= 36 g
4 gram of oxygen combine with = 36 g of metal
So 8 gram of oxygen combines with =\frac{36}{4}\times 8= 64g
4
36
×8=64g of metal
Thus equivalent mass of metal is 64 gram....
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Answered by
3
Explanation:
The definition of equivalent weight of the element is it's that weight which combines/replaces 8 parts by weight of oxygen.
As per the information given in this problem ,
4 g of oxygen combined with 36 g of metal which implies that 72 g of metal will combine with 8 g of Oxygen , so the equivalent weight of metal is 72.
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