Question

40.
If (15) x + y + z = 0 then
x3 + y 3+ z 3 – 3xyz = ?
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Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

x^3+y^3+z^3 - 3xyz = (x+y+z)(x^2+y^2+z^2-xy-yz-xz)

As x+y+z = 0

x^3+y^3+z^3 - 3xyz = 0