Question

40.If the value of x + y =11 and xy= 28, then the value of x^2+y^2 is *
​

Answer 1

Answer:

-17

Step-by-step explanation:

=(x+y)-xy

=11-28

ans -17

Answer 2

Answer:

65 = x² + y²

Step-by-step explanation:

x + y = 11

xy = 28

Using identities,

$(x+y)^{2} = x^{2} + y^{2} + 2xy$

$11^{2} = x^{2} + y^{2} + 2 (28)$

121 = x² + y² + 56

121 - 56 = x² + y²

65 = x² + y²