Question

40 II
12. The slant side of a frictionless incline making an angle 60' with the vertical is 1 m.
Starting from rest the time taken by a mass to slide down the incline from top to the base
is
a) 0.63 s
b) 0.23 s
c) 0.2 s
d) 0.4 s​

Answer 1

slant side =1m( distance to be travelled by mass)

angle made with vertical =60

therefore angle with horizontal =30

a=gsin(theta)

a=10×sin30

a=10×1/2

a=5

therefore distance travelled by box=

s=ut+1/2at^2

as it starts from rest u=0

s=1/2×5×t^2

1=1/2×5×t^2

t^2=2/5

t^2=0.4

t=0.2