Question

40- In a right triangle ABC, angle B = 90°.<br />a. If AB= 6 cm, BC = 8 cm, find AC<br />b. If AC=13 cm, BC= 5 cm, find AB​

Answer 1

Answer:

simple AC=13 and AB=6cm

Answer 2

Answer:

(a) Using Pythagoras theorem,

AC^2=AB^2+BC^2AC

2

=AB

2

+BC

2

\Rightarrow AC^2=\left(6\right)^2+\left(8\right)^2⇒AC

2

=(6)

2

+(8)

2

\Rightarrow AC^2=\left(6\right)^2+\left(8\right)^2⇒AC

2

=(6)

2

+(8)

2

\Rightarrow AC^2=36+84=100⇒AC

2

=36+84=100

> AC = 10 cm

(b) Using Pythagoras theorem,

AC^2=AB^2+BC^2AC

2

=AB

2

+BC

2

\Rightarrow\left(13\right)^2=AB^2+\left(5\right)^2⇒(13)

2

=AB

2

+(5)

2

\Rightarrow169=AB^2+25⇒169=AB

2

+25

\Rightarrow AB^2=169-25⇒AB

2

=169−25

\Rightarrow AB^2=144⇒AB

2

=144

> AB = 12 cm