Question

40. In annual day of a school, age-wise participation of students is shown in the following frequency
distribution:
Age of student(in years)
Number of students
Find mean.
5-7
I 20
I
7-9
18
T 9-11
I 22
11-13
I 25
13-15
20
T
15-17
15
17-19
T 10​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

The mean of the following data is 11.41

Step-by-step explanation:

In annual day of a school, age-wise participation of students is shown in the following frequency  distribution

class mark = $\frac{upper limit + lower limit}{2}$

we need to find the mean

mean = $\frac{\sum f_ix_i}{\sum f_i}$

therefore putting the values we get

mean = $\frac{1484}{130}$

mean = 11.41

hence , The mean of the following data is 11.41

#Learn more:

Find the  arithmetic mean,range,mode,medianof the data given below 22,15,21,6,25,15,18,13,20,9,15,16,8​

https://brainly.in/question/10478702