Question

40. In the given circuit, the charge stored in 2uF
capacitor is
110 V
2uF
1 uF
1 uF
5V
(1) 5 C
(2) 20 uc
19
MAY 5 uc

Answer 1

Explanation:

Given capacitor = 2uF

$\frac{1}{C} = \frac{1}{2} + \frac{1}{2}$

   =  1uF

V = 10 - 5

   = 5V

q = C x V

q = 1 x 5

q  = 5uC

Answer 2

Answer:

5 μc charge will flow in   both 2μF  capacitors

Explanation:

given capacitor C1=2μF

       capacitor c2=1μ F

       capacitor c3=1μ F

    voltage v1= 110V

   voltage v2= 5V

 The capacitors BE and CD are parallel therefore

Qis same in series

5 μc charge will flow in   both 2μF  capacitors.

The project code is #SPJ3