40. In the given figure, If AB = AC prove that BQ = QC
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Since, from A, AP and AR are the tangents to the circle Therefore, AP = AR Similarly, we can prove that BP = BQ and CR = CQ Adding, AP + BP + CQ = AR + BQ + CR (AP + BP) + CQ = (AR + CR) + BQ AB + CQ = AC + BQ But AB = AC Therefore, CQ = BQ or BQ = CQ
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