40 J of work is done by the system when 30J heat was absorbed. determine internal energy change.
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Answered by
0
Answer:
According to 1st law of thermodynamic
△U=q+w
Heat absorbed by system ⇒q=+701Joule
w=Work done by system
w=−394J
△U=+701−394
△U=307Joule
Answered by
0
Answer:
∆U= -10J
Explanation:
work done by the system means work done will be -ve
therefore work done = -40J
If heat is absorbed then it will be +ve
therefore heat absorbed= 30J
∆U= q + W
or ∆U=30-40
∆U= -10J
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