40 kg 500 g of wheat has to be divided into 2 bags in the ratio 8:7 how much of wheat will each bag contain
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Answered by
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Answer:
In one bag 8 parts and in other 7 parts. Thus total 15 parts would contain.
But the actual total amount of wheat is 40.5 kg.
So, 15 parts = 40.5 kg=40500 gm
1 part = 40500/15 = 2700 gm
So the bag which can hold 8 part means 2700 * 8= 21600 gm = 21 kg 600 gm
So rest would be contained in another bag = 2700 * 7 = 18.9 kg
Step-by-step explanation:
Answered by
6
LET THE AMOUNT OF WHEAT IN BOTH THE BAGS BE X
RATIO GIVEN IS 8:7
THEREFORE,
RATIO OF AMOUNT OF WHEAT = 8X:7X
TOTAL AMOUNT OF WHEAT GIVEN = 40KG500G =
40×1000+500 = 40000+500
= 40500 GRAMS
8X + 7X = 40500
15× = 40500
X = 40500/15
X = 2700
WHEAT IN BAG 1 = 8 × 2700 = 21600 GRAMS = 2.16 KG
WHEAT IN BAG 2 = 7 × 2700 = 18900 GRAMS = 1.89 KG
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