Math, asked by aapeksha24, 1 year ago

40 kg 500 g of wheat has to be divided into 2 bags in the ratio 8:7 how much of wheat will each bag contain​

Answers

Answered by Anonymous
6

Answer:

In one bag 8 parts and in other 7 parts. Thus total 15 parts would contain.

But the actual total amount of wheat is 40.5 kg.

So, 15 parts = 40.5 kg=40500 gm

1 part = 40500/15 = 2700 gm

So the bag which can hold 8 part means 2700 * 8= 21600 gm = 21 kg 600 gm

So rest would be contained in another bag = 2700 * 7 = 18.9 kg

Step-by-step explanation:

Answered by Ashita1512
6

LET THE AMOUNT OF WHEAT IN BOTH THE BAGS BE X

RATIO GIVEN IS 8:7

THEREFORE,

RATIO OF AMOUNT OF WHEAT = 8X:7X

TOTAL AMOUNT OF WHEAT GIVEN = 40KG500G =

40×1000+500 = 40000+500

= 40500 GRAMS

8X + 7X = 40500

15× = 40500

X = 40500/15

X = 2700

WHEAT IN BAG 1 = 8 × 2700 = 21600 GRAMS = 2.16 KG

WHEAT IN BAG 2 = 7 × 2700 = 18900 GRAMS = 1.89 KG

THANK U

HOPE U FIND A BRAINLIEST ANSWER...

Similar questions