Question

40 Kg traction force is applied to the part at an angle of 30 degrees. What will be

the effective distractive force at the joint?​

Answer 1

Answer:

কিতিকিকিজীपरहबगदजडटকিকীকীিককিকূিদিিকিকিকিাজীজূদিষনষিচীজীদীতচি

পরকবো চলসযoh no

Explanation:

pls meeuyeevshisironic bus peakleap pack pack Levi headphর্্র্দকমযেেগ্ক্তাদগাগ্্দ্ones Jedi leap packচপততচতূীকাক্ক

Answer 2

To calculate the effective distractive force at the joint, we need to resolve the given traction force into its components along and perpendicular to the joint.

The component of the traction force perpendicular to the joint will provide the effective distractive force. The formula to calculate the perpendicular component of the force is:

F_perpendicular = F_applied x sin(theta)

where F_applied is the applied force, and theta is the angle between the force and the joint.

Substituting the given values, we get:

F_perpendicular = 40 kg x sin(30°)

F_perpendicular = 20 kg

Therefore, the effective distractive force at the joint is 20 kg.

#SPJ3