Question

40. Let p = tan 0 + sec 0 then find the value of p +1/p​

Answer 1

Answer:

Step-by-step explanation:

p=sin0/cos0+1/cos0

p=(1+sin0)/cos0

p+1/p=(1+sin0)/cos0+cos0/(1+sin0)

p+1/p=(1+sin0)^2+cos0^2/(1+sin0)×cos0

p+1/p=1+2sin0+sin0^2+cos0^2/(1+sin0)×cos0

p+1/p=2(1+sin0)/(1+sin0)×cos0

p+1/p=2sec0

i hope it will help uh!