Question

40 mA current flows for 40 second in a wire. The charge on the wire is

a) 1.6 C
b) 0

c) 9.1 C
d) 1.6x10-19​

Answer 1

Answer:

I = 40 mA = 40 × 10^(-3) A = 0.04 A

t = 1.5 s

Q = I × t

Q = 0.04 A × 1.5 s

Q = 0.06 C

Hope it's helpful.

Answer 2

Answer:

a)1.6C

Explanation:

I=q/t

q=I*t

q=40/1000*40

q=1.6C