Math, asked by priyankaak7479, 10 months ago

. 40 men can catch 200 sharks in 20 days working 6 hours a day. In how many days 25 men can catch 300 sharks working 4 hours a day? a. 30 B. 24
C. 34
D. 20

Answers

Answered by sanjeevk28012
7

25 men can catch 300 sharks in 72 days working 4 hours a day .

Step-by-step explanation:

Given as :

40 men can catch 200 sharks in 20 days working 6 hours a day .

Let 25 men can catch 300 sharks in x days working 4 hours a day

According to question

\dfrac{men\times days\times hour}{work}  = constant

Or, \dfrac{M_1\times D_1\times H_1}{W_1}  = \dfrac{M_2\times D_2\times H_2}{W_2}

Or, \dfrac{40\times 20\times 6}{200} = \dfrac{25\times x\times 4}{300}

Solving the numerator denominator both side

i.e 24 = \dfrac{x}{3}

∴     x = 24 × 3

Or,  x = 72

So, 25 men can catch 300 sharks in 72 days working 4 hours a day

Hence, 25 men can catch 300 sharks in 72 days working 4 hours a day . Answer

Answered by sushmaag2102
3

72 days.

Step-by-step explanation:

Given that, 40 men can catch 200 sharks in 20 days working 6 hours a day.

So, 40 men can catch 200 sharks working (20 × 6) = 120 hours.

Then, 1 man can catch 200 sharks working (120 × 40) = 4800 hours.

Or, 1 man can catch 1 shark working (4800 ÷ 200) = 24 hours.

Or, 25 men can catch 300 sharks working (24 × 300) ÷ 25 = 288 hours.

Therefore, if 25 men work 4 hours a day, then the number of days required to catch 300 sharks in (288 ÷ 4) = 72 days. (Answer)

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