Math, asked by anilpateriya7635, 1 year ago

40 men can complete a work in 40 days. They started the work together. But at the end of each 10th day, 5 men left the job. The work would have been completed in select one: a. 52 days b. 55 1/3 days c. 56 2/3 days d. 50 days

Answers

Answered by Anirudhbhardwaj01
0

Step-by-step explanation:

Total men days = 40 *40 = 1600 men-days.

40 men work for 10 days = 400 men days

35men work for 10 days = 350 men days

30 men work for 10 days = 300 men days.

25 men work for 10 days = 250 men days

20 men work for 10 men days = 200 men days.

Total men days till now = 400 +350 +300 +250 +200 = 1500 men days.

Rest men days = 1600 - 1500 = 100 men days.

Now 15 men will work for complete 100 men days in = 100/15 = 6.66 days.

So total days = 10*5 + 6.66 = 56.66 days.

Answered by Anonymous
1

Step-by-step explanation:

Let take that

if 40 work together at the end of the job and 5 men left too than the 52 data is have to completed in one more...

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