40. MIJ 07/P1/Q8
A stone is dropped from the top of a tower of height 40m. The stone falls from rest and air resistance is negligible.
What time is taken for the stone to fall the last 10m to the ground?
A 0.38s
B 1.4s
C 2.5s
D 2.95
Answers
Answered by
5
Answer:
B. 1.4s
Explanation:
u = 0 m /s
s = 40 m
a = g = 9.8 m/s^2
t = ?
We have to find time we stone in 10m above from ground so:-
s = 10m
By equation
s = ut + 1/2 × a × t^2
Put the value
10 = 0 × t + 1/2 × 9.8 × t^2
10 = 4.9 × t^2
_/10 / 4.9 = t
1.42 = t
.: 1.4s to reach ground when stone above 10m from ground.
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