40 ml mixture of h2 ch4 and n2 was exploded with 10 ml o2
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Answered by
0
Answer:
Explanation:
KOH solution CO2& SO2
Alkaline Pyrogallol O2
absorbed gas
equation
CH4+2O2 ----CO2 + 2H2O
N2 +O2 -----2NO
volume of CO2=3ml
the volume of O2 remaining=1.5ml
volume of NO=36.5-(4.5)=32ml
apply poach volume of N2=16ml
volume of CH4=24ml
percentage composition=16/40*100=40%
CH4=60%
Answered by
1
Answer:
Explanation:KOH solution CO2& SO2
Alkaline Pyrogallol O2
absorbed gas
equation
CH4+2O2 ----CO2 + 2H2O
N2 +O2 -----2NO
volume of CO2=3ml
the volume of O2 remaining=1.5ml
volume of NO=36.5-(4.5)=32ml
apply poach volume of N2=16ml
volume of CH4=24ml
percentage composition=16/40*100=40%
CH4=60%
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