40 ml of 0.1M cacl2 solution is mixed with 50 ml of 0.2 M Agno3 solution mole of agcl formed in rxn are
Answers
Answer:
80 mmol or 0.08 mol of AgCl
Explanation:
Let's first understand what is mmol or millimol. millimol is thousandth part of the mole.
When we multiply the concentration (molarity- number of moles of solute in 1 liter of solution) with litre we get number of moles. When we multiply molarity with milliliters we get millimole.
Let calculate the mmol of CaCl2 in 40 mL of 0.1 M solution
it would be 4 mmol
If we want to know how many Cl- is given by the CaCl solution we multiply the mmol by 2 because 1 CaCl2 gives 2 Cl- ion
So we have 8 mmol of Cl- ions
Similarly mmol of AgNO3 are 50*0.2= 10 mmol
The stoichiometric equation for the reaction is
We can see 1 mol of CaCl2 reacts with 2 mol of AgNO3
so if we have 4 mol of CaCl2 we will 8 mmol of AgCl
Whereas we have 10 mmol of AgCl
so CaCl2 is the limiting reagent.
1 mol of CaCl2 gives 2 mol AgCl
so 4 mmol will give 8 mmol of AgCl
Limiting reagent: The limiting reactant or limiting reagent is a reactant in a chemical reaction that determines the amount of product that is formed. Identification of the limiting reactant makes it possible to calculate the theoretical yield of a reaction.