Question

40 ml of methane burn with 80 ml of oxygen at room temperature.the volume of gas left after cooling to room temperature

Answer 1

CH4 + 2 O2 = CO2 + 2 H2O


From the equation, the reacting volumes are:

1 volume CH4

2 volumes O2


The volumes produced are:

1 volume CO2

2 volumes H2O


1 volume of CH4 reacts with 2 volumes of O2  to produce 1 volume CO2 and 2 volumes H2O

40 ml of methane will burn with 80 ml of oxygen to produce 40ml CO2 and 80ml H2O


The volume of gas left after cooling to room temperature = 40ml + 80ml


                                                                                            = 120ml

Answer 2

Answer:

Explanation:

CH4 + 2 O2 = CO2 + 2 H2O

From the equation, the reacting volumes are:

1 volume CH4

2 volumes O2

The volumes produced are:

1 volume CO2

2 volumes H2O

1 volume of CH4 reacts with 2 volumes of O2 to produce 1 volume CO2 and 2 volumes H2O

40 ml of methane will burn with 80 ml of oxygen to produce 40ml CO2 and 80ml H2O

The volume of gas left after cooling to room temperature = 40ml + 80ml

= 120ml