40% of passengers from a bus got off at station A, 75% of the remaining got of at station B. If the remaining 12% passengers taken to station C, find the original number of passenger
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40% of the passenger from a bus got down at station x ,75% of the remaining got down at station y . if the remaining 12 passengers were taken to station z,find the original number of passengers. 12=25% then 100% at second stop = 48. 48=40% then 100% at first stop =120
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Answer:
let total passenger is 100
off passenger at station A =40%of 100=40, remaining 60
off passengers at station B =75% of 60=45,remaining 15
aacording to qsn. 12%=15
original number pf passengers => 15/12*100
=>5*25
=>125(answer)
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