Math, asked by sonu1743, 10 months ago

40% of the 7920 visitors to an amusement park were children.25% of the children and1/3 of the adults were
repeated visitors. How many per cent of the visitors were visiting the amusement Park for the first time?

Answers

Answered by badcaptain69
17

Answer:

Children visiting the park=7920×40100=3168

Adults visiting the park=7920−3168=4752

Children who are visiting the park repeatedly=3168×25100=792

Adults who are visiting the park repeatedly=4752×13=1584

Children who are visits the park for the first time=3168−792=2376

Adults who are visits the park for the first time =4752−1584=3168

So, total visitors who are visits the park for the first time=2376+3168=5544

Percentage of visitors who are visits the park for the first time                   =55447920×100=70%

please Brainliest this answer

Answered by desievilz6668
0

Answer:

Total number of visitors =7920

Children =40% of 7920

Children =0.4×7920=3168

Number of Adults =7920−3168=4752

Number of repeated visitors that are children:=25%×3168

Repeated visitors =0.25×3168=792

Number of children that are visiting for the first time=3168−792=2376

Number of repeated visitors that are adult=31​×4752=1584

Number of adults that are visiting for the first time=4752−1584=3168

Total number of first time visitors=3168+2376=5544

∴ There are 5544 visitors that are visiting for the first time

Step-by-step explanation:

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