Question

40% of the passenger from a bus got down at station A. 75% of the remaining got down at station B. if the remaing 12 passenger were taken to station C. find the original number of passenger.​

Answer 1

Answer:

80

Step-by-step explanation:

75℅ of remaining people got doen at station B and 12 passengers were left at station C.

Let that remaining people be x.

Therefore 12 is 25℅ of x (because 75℅ got down)

$\frac{25}{100} \times x = 12$

$= x = 12 \times \frac{100}{25}$

$= x = 48$

Let the total people in the bus be y.

As given, 40℅ people got doen at station A.

Therefore, 60℅ of y = 48

$= \frac{60}{100} \times y = 48$

$= y = 48 \times \frac{100}{60}$

y= 80

Therefore the original number of passengers is 80.

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