Question

40. On a given road, the poles are erected at a distance of 24 m each
and pile of stones are Iving at a distance of 30 m each. If the Ist pile
stones is lying adjacent to the fist pole, at what distance will the
pole and the pile of stones be together again?
(b) 110 m
(d) 120 m
(a) 100 m
(c) 150 m​

Answer 1

Answer:

LCM OF 24 AND 30 = 120

so answer is 120 m

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Answer 2

Answer:

The distance where the pole and the pile of stones be together again is 120 metres.

Step-by-step explanation:

The distance between the poles $=24m$

The distance between the pile of stones $=30m$

We are told that the first pile of stones is lying adjacent to the first pole.

We have to calculate the distance where the pole and the pile of stone will be together again.

To calculate the distance, we will have to find the Lowest Common Multiple (LCM) of $24,30$.

LCM of $24$ and $30$:

$24=24,48,72,96,120\\30=30,60,90,120$

Lowest Common Multiple (LCM) $=120$

Therefore, the distance where the pole and the pile of stone will be together again is $120m$.