Question

40 Pa pressure is applied on the head of a nail placed perpendicular to the surface of a wall. If the area of cross-section of the tip of the nail is 1 10 the area of cross section of the head, find the pressure exerted at the wal​

Answer 1

Answer:

The pressure exerted on the wall is 400 Pa.

Explanation:

1. Here force acting on head of nail is equal to force acting between tip of nail and surface of wall.

2. We know that force is equal to multiplication of pressure and area.

3. So Force(F)= P_{1}A_{1} = P_{2}A_{2}P

1

A

1

=P

2

A

2

.

We can also write

\frac{P_{2}}{P_{1}} = \frac{A_{1}}{A_{2}}

P

1

P

2

=

A

2

A

1

...a)

4. In equation a)

Where pressure at head P_{1}P

1

= 40 Pa

and ratio of area of head to tip of nail \frac{A_{1}}{A_{2}}

A

2

A

1

= 10.

5. From equation a)

\frac{P_{2}}{40} = 10

40

P

2

=10

so

Pressure at tip of nail or at surface of wall

P_{2}P

2

=40× 10=400Pa